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design of machine that build magnetic rails for magnetic vehicle or train
Building the bird (the finger?) on wheels with various versions of electric, magnetic and potentially steam powered engines.
Designed to Reach Mach 1 without rocket fule : extreme propulsion metrics : full braking system : configured in-air or on-ground slowdown and speed up mechanisms
Candles not included for gaseous emissions, cow's methane gas, tiny whoopie cushion-esk noises, etc.
Currently, acquiring materials to build mentioned designs.
Current vehicle requires 87, 91, etc or ethanol boosted gasoline to acquire materials. Gasoline currently for sale a wide selection of gas stations in various areas.
Design Modification 07.15.2026 : speed up and slow down design modification
Braking system modification 07.24.2026 : braking system design modification
potentially important safety design sidenote: coils (bed coils? ) between high grade strong PVC, etc. plastic in between thick home depot or Lowe's grade foam to ensure driver or driverless machine security.
To turn a 201 lb (91.2 kg) axle and wheel assembly, the required magnetic pull force is not a single fixed number. It depends heavily on how the magnetic force is being applied (e.g., pulling a lever arm to rotate it vs. using a magnetic wheel on a track) and the mechanical friction of the bearings.
To determine the exact force, we have to look at the math behind two different scenarios:
Scenario 1: Overcoming Bearing Friction (Torque to Spin)
If the 201 lb assembly is sitting on bearings and you want to use a magnet to start spinning it, the magnet must overcome the static bearing friction.
Assuming high-quality, standard ball bearings, the coefficient of friction (
μmu
𝜇) is roughly 0.0015.
Frictional Force:
201 lbs×0.0015=𝟎.𝟑𝟎𝟏𝟓 lbs of linear force at the bearing radius.
The Leverage Factor: If your magnet pulls on the outside of a large wheel, it has a mechanical advantage over the smaller axle bearing. If it pulls directly on a 1-inch radius axle, you need ~0.3 lbs of tangential magnetic force. If it pulls on a 10-inch radius wheel, you only need ~0.03 lbs of force.
Scenario 2: Rolling Resistance (Moving the Wheel Across a Floor)
If the 201 lb assembly is resting on the ground and you are using a magnet to pull it forward so it rolls:
Steel wheels on steel rails: The rolling resistance coefficient is about 0.002. You would need roughly 0.4 lbs of magnetic pulling force.
Rubber tires on concrete: The coefficient is about 0.015. You would need roughly 3.0 lbs of magnetic pulling force.
Approximatly DOUBLE the pull force? The design of the Automation Anytime Magnetic Vehicle (materials currently being purchased and some things being built) is to time accurately at various intervals the speed up and slow down of various vehicle weights.
Important: "Pull Force" vs. "Shear Force"
When magnet manufacturers list a magnet's Pull Force, they mean the breakaway force required to pull a magnet straight off a thick steel plate.
Supreme Magnets
If you are using a magnetic wheel or an actuator where the magnet is sliding or trying to rotate a surface sideways, you are dealing with Shear Force. In magnetic setups, the sliding/shear force is typically only 15% to 25% of the magnet's rated perpendicular pull force due to surface friction.
Radial Magnets +2
Rule of Thumb: If the physics above say you need 3 lbs of actual kinetic force to roll the wheel, you should look for a magnet rated for at least 12 to 20 lbs of standard pull force to account for shear loss and a safety margin.
Dhit.pl
To calculate the exact magnet size you need, could you clarify:
Is the magnet spinning the axle like a motor, or pulling the entire assembly forward along a surface?
What are the diameters of both the axle and the wheel?
What materials are the wheels and the surface they rest on made of?
python
# Calculate the torque required to turn an axle and wheel weighing 201 lbs.
# Since we don't have the radius of the wheel/axle, or the friction coefficient, let's provide the fundamental formulas and a quick lookup for standard rolling resistance.
weight_lbs = 201
weight_n = weight_lbs * 4.44822
print(f"Weight in Newtons: {weight_n}")
Dhit.pl
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